An engineer is designing an open box (without top) with a square base. The box's volume must be 2900 in
^(3)
. The engineer wants to minimize the box's surface area. Note that the volume of the box is
V=hx^(2)
. We can write the box's surface area,
S(x)
, as a function of
x
:
S(x)=4xh+x^(2)
S(x)=4x((2900)/(x^(2)))+x^(2)
S(x)=(11600)/(x)+x^(2)
Use a graphing utility to find the value of
x
and
h
such that the box has a minimum surface area. Round your answers to two decimal places and include units. The box has a minimum surface area of
◻
when its base's side length is
◻
and the box's height is (Use in for inches and in
^(^())2
for square inches.)