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(Solved): Charge Q_(1)=27.91mC is placed R=33.65cm to the left of charge Q_(2)=62.73mC, as shown in the figure ...



Charge

Q_(1)=27.91mC

is placed

R=33.65cm

to the left of charge

Q_(2)=62.73mC

, as shown in the figure. Both charges are held stationary. Point A is located

R_(3)=10.10cm

to the right of

Q_(1)

. A particle with a charge of

q=-3.051\mu C

and a mass of 26.81 g is placed at rest at a distance

R_(2)=30.29cm

above

Q_(2)

. If the particle were to be released from rest, calculating its exact path would be a challenging problem. However, it is possible to make some definite predictions about the future motion of the particle If the path of the particle were to pass through point A , what would be its speed

v_(A)

at that point?

v_(A)=

(m)/(s)
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