(Solved): (1 point)   Suppose f(x)=x211f(x)=x211. (a) The rectangles in the graph A illustrate&n ...

(1 point)

Suppose f(x)=x211f(x)=x211. (a) The rectangles in the graph A illustrate f(x)f(x) on the interval 2?x?62?x?6. The area of all the rectangles is  , and it is an   ?    overestimate of    equal to    underestimate of    there is ambiguity     the area of the region enclosed by y=f(x)y=f(x), the x-axis, and the vertical lines x=2x=2 and x=6x=6. (b) The rectangles in the graph B illustrate for f(x)f(x) on the interval 2?x?62?x?6. The area of all the rectangles is  , and it is an   ?    overestimate of    equal to    underestimate of    there is ambiguity     the area of the region enclosed by y=f(x)y=f(x), the x-axis, and the vertical lines x=2x=2 and x=6x=6.

Graph A   Graph B

(c) To get a more accurate approximation of the area, the number of rectangles should:  ? increase decrease exact number of  rectangles.

Note: Your objective is to find an approximation of the area under the curve on the interval 2?x?62?x?6 using the areas of each of the sets of rectangles.

Suppose \( f(x)=\frac{x^{2}}{11} \) (a) The rectangles in the graph A illustrate \( f(x) \) on the interval \( 2 \leq x \leq 6 \). The area of all the rectangles is and it is an the area of the region enclosed by \( y=f(x) \), the \( x \)-axis, and the vertical lines \( x=2 \) and \( x=6 \). (b) The rectangles in the graph B illustrate for \( f(x) \) on the interval \( 2 \leq x \leq 6 \). The area of all the rectangles is and it is an the area of the region enclosed by \( y=f(x) \), the \( x \)-axis, and the vertical lines \( x=2 \) and \( x=6 \). (c) To get a more accurate approximation of the area, the number of rectangles should: rectangles. Note: Your objective is to find an approximation of the area under the curve on the interval \( 2 \leq x \leq 6 \) using the areas of each of the sets of rectangles.