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(Solved): 1) What was oxidized ? N2H4 + O2 --> N2 + 2H2O 2) Which is NOT an oxidation-reduction equatio ...



1) What was oxidized ? N2H4 + O2 --> N2 + 2H2O

2) Which is NOT an oxidation-reduction equation?

4Fe + 3O2 --> 2Fe2O3

CuO + H2 --> Cu + H2O

2Na + H2 --> 2NaH2

Cu( s) + 2AgCl( aq) --> 2Ag( s) + CuCl2( aq)

2HCl + Ba(OH) 2 --> BaCl2 + 2H2O



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1)N2H4 + O2 --> N2 + 2H2O oxidation number of N2 in free state =0and in N2H4 it has -2
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