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(Solved): 10. A ball of mass m = 0.010 kg and charge q is tied by a very light string to the ceiling. The effe ...



10. A ball of mass m = 0.010 kg and charge q is tied by a very light string to the ceiling. The effects of a uniform electric field E = 5000 N/C has caused the charged ball to move to one side so that the string makes an angle of 0 = 37° with the vertical. Draw the free body diagram of the floating ball. Determine the magnitude of the charge q. How can you tell the sign (positive or negative) of the charge? I

10. A ball of mass \( m=0.010 \mathrm{~kg} \) and charge \( q \) is tied by a very light string to the ceiling. The effects o
10. A ball of mass and charge is tied by a very light string to the ceiling. The effects of a uniform electric field has caused the charged ball to move to one side so that the string makes an angle of with the vertical. Draw the free body diagram of the floating ball. Determine the magnitude of the charge q. How can you tell the sign (positive or negative) of the charge?


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Step 1: Draw the free body diagram of the floating ball The ball is suspended from the ceiling by a thin string. There are two forces acting on the ball: the tension force from the string and the electric force due to the uniform electric field. The free body diagram is shown below:
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