2.21 Determine V0? and I in the circuit in Fig P2.21. Figure P2.21 LUTION: We apply KVL around the loop. The result is, ?12+4l+2v0??4+6l=0 Applying Ohm's law to the 6?? resistor gives dont undessicind V0?=?6I Substituting in (i), we get, ?16+10I?12I=0?I=?8AandV0?=48V

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2.21 Determine V0? and I in the circuit in Fig P2.21. Figure P2.21 LUTION: We apply KVL around the loop. The result is, ?12+4l+2v0??4+6l=0 Applying Ohm's law to the 6?? resistor gives  dont undessicind V0?=?6I Substituting in (i), we get, ?16+10I?12I=0?I=?8AandV0?=48V

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(Solved): 2.21 Determine V0 and I in the circuit in Fig P2.21. Figure P2.21 LUTION: We apply KVL around th ...

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