(Solved): 2 points You run an experiment to study the reaction below. You plan to fill your container with \ ...

2 points You run an experiment to study the reaction below. You plan to fill your container with \( \mathrm{NOBr} \) to a concentration of \( 6.75 \times 10^{-3} \mathrm{M} \). \( 2 \mathrm{NOBr}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{Br}_{2}(g) \quad K=6.84 \times 10^{-8} \) Using the \( x \) is small approximation, what is the expected concentration of \( \mathrm{NOBr} \) at equilibrium? \( (0.01, \mathrm{SN}) \) Type your answer... 2 points You run an experiment to study the reaction below. You plan to fill your container with NOBr to a concentration of \( 6.75 \times 10^{-3} M \). \( 2 \mathrm{NOBr}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{Br}_{2}(g) \quad K=6.84 \times 10^{-8} \) Using the \( x \) is small approximation, what is the expected concentration of NO at equilibrium? \( (0.01, \mathrm{SN}) \) Type your answer. 2 points You run an experiment to study the reaction below. You plan to fill your container with NOBr to a concentration of \( 6.75 \times 10^{-3} \mathrm{M} \). \( 2 \mathrm{NOBr}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{Br}_{2}(g) \quad K=6.84 \times 10^{-8} \) Using the \( x \) is small approximation, what is the expected concentration of \( \mathrm{Br}_{2} \) at equilibrium? \( (0.01, \mathrm{SN}) \) Type your answer... 2 points You run an experiment to study the reaction below. You plan to fill your container with NOBr to a concentration of \( 6.75 \times 10^{-3} \mathrm{M} \). \( 2 \mathrm{NOBr}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{Br}_{2}(g) \) \[ K=6.84 \times 10^{-8} \]