(Solved): 3. Let \( A=\left[\begin{array}{lll}1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9\end{a ...
![3. Let \( A=\left[\begin{array}{lll}1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9\end{array}\right] \).
(10 points)
(a) Find a basis fo](https://media.cheggcdn.com/media/f9e/f9e34769-a43a-415b-9cc2-572819848b45/phpJhtLwl)
3. Let \( A=\left[\begin{array}{lll}1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9\end{array}\right] \). (10 points) (a) Find a basis for the column space of \( A \). (b) Find a basis for the nullspace of \( A \). (c) Verify that the dimension theorem holds for \( A \).
Expert Answer
Solution:- Given matrix is A=[123456789] The row echelon form of the matrix is =[1230?3?6000]