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4-methyl-3-hexanol-was-prepared-by-reacting-an-alkene-with-either-hydroboration-oxidation-or-oxymer-pa800
(Solved): 4-methyl-3-hexanol was prepared by reacting an alkene with either hydroboration-oxidation or oxymer ...
4-methyl-3-hexanol was prepared by reacting an alkene with either hydroboration-oxidation or oxymercuration-reduction. Draw the structure of the alkene that was used to prepare the alcohol in highest yield. - You do not have to consider stereochemistry. - Indicate the method of preparation by drawing either BH3 (for hydroboration-oxidation), or Hg (for oxymercuration-reduction) in a separate sketc - If there is more than one alkene that can be used for a given method, draw all of them. - If either hydroboration-oxidation or oxymercuration-reduction can be used, just give the structures for one method. - Separate structures with + signs from the drop-down menu.