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(Solved): (4) Suppose G is a group of order 100 (this means G has 100 elements). Prove that G must have an ele ...



(4) Suppose

G

is a group of order 100 (this means

G

has 100 elements). Prove that

G

must have an element

a!=e

satisfying

a^(2)=e

. (We say "

a

has order 2.") [Hint: Try proving this by contradiction] Can you generalize the statement for a group of order

2n

?



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