(Solved): (6) Can A contains 80 liters of paint that is 1/4 red and the rest is blue. Can B contains 100 lite ...

(6) Can $A$ contains 80 liters of paint that is $1/4$ red and the rest is blue. Can $B$ contains 100 liters of paint of which 20 liters is blue and the rest is red. (a) If one quarter of the paint in Can A is mixed with $30\%$ of the paint in Can B, what is the percentage of red paint in the resulting mixture? $\%$ of red paint is (b) If 50 liters of paint is made by mixing $x$ liters from Can A and the remainder of the 50 liters comes from Can B, then what is the percentage of red paint in the mixture? The answer is $(A+Bx)\%$ where (c) The paint in can A costs $\$22$ per liter and the paint in can B costs $\$55$ per liter. A customer want 50 liters of paint that is $40\%$ red and the rest is blue. How many dollars does the paint cost the customer? The answer is a whole number $\mathrm{cost}=[$