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(Solved): 6. For all integers \( a, b \), and \( c \) If \( a \mid(b+c) \) then \( a \mid b \) or \( a \mid c ...






6. For all integers \( a, b \), and \( c \) If \( a \mid(b+c) \) then \( a \mid b \) or \( a \mid c \).
7. For all integers \
For each of the following statements, either prove the statement or give a counterexample that shows the statement is false.
6. For all integers \( a, b \), and \( c \) If \( a \mid(b+c) \) then \( a \mid b \) or \( a \mid c \). 7. For all integers \( m \), if 7 is a factor of \( m \) then 7 is not a factor of \( m+6 \). 8. \( (\forall x \in \mathbb{1}) \mid \sqrt{x} \in \mathbb{I}] \) 9. \( (\forall x, y \in \mathbb{Q})(\forall z \in \mathbb{I})[ \) If \( y \neq 0 \) then \( x+y z \in \mathbb{I}] \) 10. \( \log _{5}(2) \in 1 \). Hint: Consider using the Fundamental Theorem of Arithmetic. For each of the following statements, either prove the statement or give a counterexample that shows the statement is false. We will use the (non-standard) notation I to represent the irrational numbers. Each problem is worth 10 points.


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solution 6 - The given statement is false. Counterexample: Take a=3,b=1,c=2 ?b+c=1+2=3 Now 3?3 but 3?1 and 3?2 That is a?(b+c) but a?b and a?c Hence t
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