(Solved): 6. For matrix A=202142101. a. Show that 101 ...
6. For matrix A=⎣⎡20−2−14−2−101⎦⎤. a. Show that ⎣⎡10−1⎦⎤ is an eigenvector of A and find the corresponding eigenvalue. (4) b. Show that 4 is an eigenvalue of A and find an eigenvector associated with it. (4) c. Show that def(A)=0. (4) d. Is A invertible? Briefly explain! e. From the observation that der(A)=0, deduce the value of the third eigenvalue of A and find an eigenvector associated with it.
(a)Characteristic equation (2- ){(4- (1- Thus, the EIGEN VALUE OF MATRIX A are 0,3,4when the corresponding eigen vector is given by -x-y-z=0 .......(1)0.x+y+0.z=0 ..........(2)-2x-2y-2z=0 ......(3)from eqn.(2)y=0put y=0 in eqn.(3)then we get -x-z=0-x=z .....(4)therefore put x=1 in eqn.(4) we get z=-1then the eigen vector= hence proved.