(Solved): 8 and 14 only \( \begin{array}{ll}\text { 1. If } f(2)=12 \text { and } g(2)=4 \text {, then }(g-f)( ...

\( \begin{array}{ll}\text { 1. If } f(2)=12 \text { and } g(2)=4 \text {, then }(g-f)(2)= & \text { In Exercises 11-22, functions } f \text { and } g \text { are given. Find each of }\end{array} \) 2. If \( f(x)=2 x-1 \) and \( f(x)+g(x)=0 \), then \( g(x)= \) the following functions and state its domain. a. \( f+g \) b. \( f-g \) c. \( f+g \) 3. If \( f(x)=x \) and \( g(x)=1 \), then \( (f \circ g)(x)= \) d. \( \frac{f}{g} \) e. \( \frac{\mathrm{R}}{f} \) 11. \( f(x)=x-3 ; g(x)=x^{2} \) 4. If \( f(1)=4 \) and \( g(4)=7 \), then \( (g * f)(1)= \) 12. \( f(x)=2 x-1: g(x)=x^{2} \) 5. True or False. If \( f(x)=2 x \) and \( g(x)=\frac{1}{2 x} \), then 13. \( f(x)=x^{3}-1: g(x)=2 x^{2}+5 \) \( (f \circ g)(x)=x \). 14. \( f(x)=x^{2}-4 \cdot g(x)=x^{2}-6 x+8 \) 6. True or False. ft cunnot happen that \( f \circ g=g \circ f \). 15. \( f(x)=2 x-1: g(x)=\sqrt{x} \) In Exercises 7-10, functions \( f \) and \( g \) are given. Find each of 16. \( f(x)=1-\frac{1}{x^{4}} g(x)=\frac{1}{x} \) the given values, a. \( (f+g)(-1) \) b. \( (f-g)(0) \) 17. \( f(x)=\frac{2}{x+1} \cdot g(x)=\frac{x}{x+1} \) c. \( (f \cdot g)(2) \) d. \( \left(\frac{f}{R}\right)(1) \) 18. \( f(x)=\frac{5 x-1}{x+1} \cdot g(x)=\frac{4 x+10}{x+1} \) 7. \( f(x)=2 x ; g(x)=-x \) 19. \( f(x)=\frac{x^{2}}{x+1} \cdot g(x)=\frac{2 x}{x^{2}-1} \) 8. \( f(x)=1-x^{2}+g(x)=x+1 \) 20. \( f(x)=\frac{x-3}{x^{2}-25^{.}} g(x)=\frac{x-3}{x^{2}+9 x+20} \) 10. \( f(x)=\frac{x}{x^{3}-6 x+8^{4}} x(x)=3-x \) 21. \( f(x)=\frac{2 x}{x^{2}-16} g g(x)=\frac{2 x-7}{x^{2}-7 x+12} \) 22. \( f(x)=\frac{x^{2}+3 x+2}{x^{3}+4 x} \cdot g(x)=\frac{2 x^{3}+8 x}{x^{2}+x-2} \)