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Question Details
| Item Name | Price |
|---|---|
| Expert Answer #2956792 y^(')=-(2y)/(x) Cpx^(p-1)=-2Cx^(p) pCx^(p-1)=-2Cx^(p-1) pCx^(p-1)=-2Cx^(p)Could you explain how the ... | $5 |
| TOTAL | $5 |
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