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(Solved): A = 89 B = 9 C = 8 Consider two positive charges separated by a distance ((A+20)/100) meters. One ch ...



A = 89

B = 9

C = 8

Consider two positive charges separated by a distance ((A+20)/100) meters. One charge has a value of (B + 5)mC (milli-coulombs) and is located to the right of the other (C + 5)mC charge. Assume the left charge is the origin and the other charge is located with a positive horizontal position. How large and in what direction is the electrostatic field at the mid-point, directly between the two charges? Use i-notation for the direction.

Calculate the answer in newtons per coulomb (N/C) and make sure to include the unit. Report your final answer with two significant figures and if you need to use scientific notation, i.e. 352 000 000 would be written as 3.52E8 (or 3.52 × 108)



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