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(Solved): A,B, & C Assume that \( 20.8 \% \) of people have sleepwalked. Assume that in a random sample of ...
A,B, & C
Assume that \( 20.8 \% \) of people have sleepwalked. Assume that in a random sample of 1522 adults, 331 have sleepwalked. a. Assuming that the rate of \( 20.8 \% \) is correct, find the probability that 331 or more of the 1522 adults have sleepwalked. b. Is that result of 331 or more significantly high? c. What does the result suggest about the rate of \( 20.8 \% \) ? a. Assuming that the rate of \( 20.8 \% \) is correct, the probability that 331 or more of the 1522 adults have sleepwalked is (Round to four decimal places as needed.)
Expert Answer
Solution: Given data is p = 0.208 n = 1522 By using binomial distribution P(x)=(nCx)×(p)x×(1?p)n?x ;x=0,1,…..,n a. As