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(Solved): A block with a mass of 12.3g and a charge of +3.81105C is placed in an electric field with x ...
A block with a mass of 12.3g and a charge of +3.81×10−5C is placed in an electric field with x component Ex=2.91×103N/C,y component Ey=−799N/C, and z component Ez=0. (a) What is the magnitude of the electrostatic force on the block and (b) what angle does that force make with the positive x direction? If the block is released from rest at the origin at time t=0, what are its (c) x and (d) y coordinates at t=3.03s ? (a) Number Units (b) Number Units (c) Number Units (d) Number Units
Given, mass M=12.3gCharge c=3.18 CEx=2.91 N/CEy=-799N/CEz=0Ex,Ey, EZ are the components of the electric field concerning x y, and z coordinates (a) The magnitude of the electrostatic force in the block is calculated as(i) We need to calculate the total Electric field = = = = =3017.69 N/CTotal Electric field =3017.69N/C(ii)The magnitude of the electrostatic force on the block can be calculated as F=qxEq= charge E= total electric field F= ( =0.114NTherefore, the magnitude of the electrostatic force on the block is approximately 0.114 N