(Solved): A cord passing over a pulley connects two masses, as shown, where m1=3.80kg and m2=8.50kg ...

A cord passing over a pulley connects two masses, as shown, where $$m_1=3.80\mathrm{kg}$$ and $$m_2=8.50\mathrm{kg}$$. Assume the pulley and surfaces are frictionless, and the cord is massless and does not stretch. (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign.) (a) What is the acceleration of each block? (Enter the magnitude in $$\mathrm{m}/{\mathrm{s}}^2$$.) 24 Draw free-body diagrams for each block. Consider rotating your axes so that the $$x$$-axis is parallel to the incline in both cases. Note that the tension in the cord is the same. Write Newton's second-law equations in the $$x$$-direction for both masses, solve for $$T$$, and set your results equal. Solve your new equation for a. $$\mathrm{m}/{\mathrm{s}}^2$$ (b) What is the tension in the cord (in $$\mathrm{N}$$ )? N