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(Solved): (a) \cup u_(\alpha inR){\alpha }\times [0,1]= (b) \cap n_(\alpha inR){\alpha }\times [0,1]= ...



(a) \cup u_(\alpha inR){\alpha }\times [0,1]= (b) \cap n_(\alpha inR){\alpha }\times [0,1]=


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