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a-e please

19) The resistance of $R_{1}$ is $5Ω$ and $R_{3}$ is $10Ω$. $R_{2}$ is made of a nichrome wire (resistivity of $1.5×10=0m$ ) that is $8m$ long and has a cross-sectional area of $6×10_{∘}m_{∗}$ The voltage of the battery is $12V$. a) What is the resistance of the wire that makes R:? b) Fill out a VIRP.chart c) How many electrons go through the "main wire" (wire connected to the baftory) each minute? d) Write Kirchhoff's Current Law for this circuit e) Write Kirchhoff s Voltage Law for each loop

Given: The resistance of R1 is 5 ? and R2 is 10 ? R2 is made of nichrome wire ( resistivity of 1.5 * 10 ^(-2)

?m that is 8 m long and has a cross-sectional area of (6 x 10^(-6) m^2). The voltage of the battery is 12V

a) To find the resistance of the wire that makes R2:

Here To find the resistance of the wire that makes R, we need to use the formula:

Resistance = (resistivity x length) / area

Resistance of R2 = (1.5 x 10^(-2) ?m x 8m) / (6 x 10^(-6) m^2)

Resistance of R2 = 200 ?

So the total resistance of the circuit is:

R = R1 + R2 = 5? + 200? = 205?

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