(Solved): \[ A=\left[\begin{array}{rrr} -3 & 0 & 5 \\ x & 0 & 0 \\ 2 & 0 & 4 \end{array}\right] \] Evaluate \ ...

\[ A=\left[\begin{array}{rrr} -3 & 0 & 5 \\ x & 0 & 0 \\ 2 & 0 & 4 \end{array}\right] \] Evaluate \( \operatorname{det}(A) \) by expanding it according to (a) the first row; (b) the third column; (c) the easiest row or column.