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(Solved): a) log_(3)x=log_(3)24 b) logx=3log2 c) log_(5)x=log_(5)3+log_(5)7 d) log_(2)(x-4)=4 e) log(2x-4)=1 f ...
a)
log_(3)x=log_(3)24b)
logx=3log2c)
log_(5)x=log_(5)3+log_(5)7d)
log_(2)(x-4)=4e)
log(2x-4)=1f)
log_(2)(7x+8)=6g)
log_(x)9=2h)
log_(2)(x+2)=-2i)
logx+log(5x)=3ј)
log_(2)(54x)-log_(2)27=7k)
log_(2)(3x)+log_(2)x=(1)/(2)log_(2)729
log_(3)(x+4)+log_(3)(x-4)=2