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(Solved): A piece of iron is heated to \( 95^{\circ} \mathrm{C} \) and dropped into \( 150 \mathrm{~g} \) of ...




A piece of iron is heated to \( 95^{\circ} \mathrm{C} \) and dropped into \( 150 \mathrm{~g} \) of water at \( 25^{\circ} \ma
A piece of iron is heated to \( 95^{\circ} \mathrm{C} \) and dropped into \( 150 \mathrm{~g} \) of water at \( 25^{\circ} \mathrm{C} \). When equilibrium is reached the temperature of water and iron is \( 33^{\circ} \mathrm{C} \). What is the mass of iron? (The specific heat of iron is \( 0.444 \mathrm{~J} / \mathrm{g}^{\circ} \mathrm{C} \) and the specific heat of water is \( 4.184 \mathrm{~J} / \mathrm{g}^{\circ} \mathrm{C} \) )


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Initially, iron was at a higher temperature than water. Hence, heat will flow from the iron to water till the equilibrium temperature is reached. Assuming no heat escapes the system of iron and wa
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