A rock contains 0.538 mg
^(206)Pbfor every 1.000 mg
^(238)Upresent. Assuming that no lead was originally present, that all the
^(206)Pbformed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between
^(238)Uand
^(206)Pbis negligible, calculate the age of the rock. (The atomic mass of
^(206)Pbis 205.97 u and the atomic mass of
^(238)Uis 238.05 . For
^(238)U,
t_((1)/(2))=4.5\times 10^(9)years.) Age
=
◻years