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(Solved): A small mailbag is released from a helicopter that is descending steadily at 2.93(m)/(s). (a) After ...
A small mailbag is released from a helicopter that is descending steadily at
2.93(m)/(s). (a) After
5.00s, what is the speed of the mailbag?
v=
◻
(m)/(s)(b) How far is it below the helicopter?
d=
q,
m(c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at
2.93(m)/(s)?
v=
◻
(m)/(s)
d=
◻m Need Help?
◻