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(Solved): A softball player stands at the top of a \( 30.0 \mathrm{~m} \) high building. She throws the softb ...
A softball player stands at the top of a \( 30.0 \mathrm{~m} \) high building. She throws the softball up in the air, releasing it at a height of \( 1.22 \mathrm{~m} \) above the top of the building. The ball travels up exactly vertically with respect to the earth. When the ball falls back down, she doesn't catch it, so it falls all the way to the ground. If she threw the ball up initially at a speed of \( 11.8 \mathrm{~m} / \mathrm{s} \), what is the total time that the ball is in the air?