(Solved): A spring with a 7-kg mass and a damping constant 9 can be held stretched 2 meters beyond its natura ...

A spring with a 7-kg mass and a damping constant 9 can be held stretched 2 meters beyond its natural length by a force of 4 newtons. Suppose the spring is stretched 4 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value $c^2-4mk$ ? ${\mathrm{m}}^2{\mathrm{kg}}^2/{\sec }^2$ Find the position of the mass, in meters, after $\mathrm{t}$ seconds. Your answer should be a function of the variable t of the form $c_1{e}^{\alpha t}+c_2{e}^{\beta t}$ where $\alpha =$ (the larger of the two) $\beta =$ (the smaller of the two) $c_1=$ $c_2=$