(Solved): about the vertical axis of rotation is given by I=121mw2. opposite side with the same force ...

about the vertical axis of rotation is given by $I=\frac{1}{12}m{w}^2$. opposite side with the same force. What is the net torque, in $\mathrm{N}\cdot \mathrm{m}$, applied to the door? $\mathrm{N}\cdot \mathrm{m}$ (b) What is the angular acceleration of the door in $\mathrm{rad}/\mathrm{s}$ ? $\mathrm{rad}/{\mathrm{s}}^2$ moment of inertia of the door about this new axis of rotation is given by $I=\frac{1}{3}m{w}^2$, where $m$ is the mass and $w$ is the width of the door. that produced by both of you in part (a) above? $\mathrm{N}$ (d) What is the angular acceleration of the door in $\mathrm{rad}/\mathrm{s}$ ? $\mathrm{rad}/{\mathrm{s}}^2$