(Solved): again, with numerical values in \( \mathrm{cm} \). What is the displacement vector \( \vec{r} \) fr ...

again, with numerical values in \( \mathrm{cm} \). What is the displacement vector \( \vec{r} \) from the source [Enter your answer with the following format: \( X^{*} i+Y^{*} j+Z^{*} k \), where you substitute the expression. The letters \( \mathrm{i}, \mathrm{j} \), and \( \mathrm{k} \) represent the unit vectors along different directions. Correct, computer gets: \( 5^{*} i-6^{*} j+7^{*} k \) Hint: Displacement is the difference between two position vectors. For a refresher on v 2. Calculate the distance \( r \) between the source particle and the target location. \( r= \) Not yet correct, tries \( \theta / 2 \theta \) wector? In thas nequence of problems, Thi gride you through the calculation of the clectric field of a clarged particle at sone givea target location. The source purticle has charge 2 aiC and is locatedat \[ \vec{r} s=-3 \hat{i}+2 \hat{j}+5 \hat{k} . \] All meanaresenents in in The target location is \[ \dot{T}=3 \hat{i}-2 \hat{j}+11 \hat{k} \] agam, with eamserical values in cm. warce-ts target stivpiacement \( = \) 5. What is the solince-to-target dirtance \( r \) ? precisien. electric ficla vetor \( = \) 9. The electric focce law states that the electric field force oa a target particle wist charge \( q \) located at positioa \( (x, y, 7) \) is \[ \vec{F}_{n}=q \vec{E}(x, t, z) \text {. } \] \( y=-1 \) cos. and \( z=13 \mathrm{~cm} \). What is the clectric force vector at the location of the tagget particle? troc, thess eater 'XYZ:]