(Solved): Any help would be much appreciated! Thank you! In a population of squirrels there is a dominant ...

Expert Answer

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To decide the genotypic recurrence of the heterozygous condition, we want to think about the Solid Weinberg rule. As per this rule, in an enormous populace where mating is irregular and no developmental powers are acting, the frequencies of alleles and genotypes stay consistent from one age to another.

Let's assume "B" addresses the predominant allele (for thick tail) and "b" addresses the passive allele (for smooth tail).

Considering that the passive characteristic (smooth tail) is constrained by a latent quality, we can reason that the squirrels with smooth tails (passive quality) should be homozygous latent (bb). Consequently, the recurrence of the latent allele (b) can be determined as follows:

Frequency of recessive allele (b) = (Number of smooth-followed squirrels)/(All out number of squirrels) = 345/950 = 0.363.

Since the passive allele (b) is just present in the homozygous latent condition (bb), the recurrence of the predominant allele (B) not entirely set in stone by deducting the passive allele recurrence from 1:


Frequency of dominant allele (B) = 1 - Frequency of latent allele (b) = 1 - 0.363 = 0.637.



As per the Hardy-Weinberg principle, the genotypic frequencies of alleles stay consistent in a populace over ages in the event that specific circumstances are met. In this situation, with 345 out of 950 squirrels having the passive smooth tail attribute, the genotypic recurrence of the heterozygous condition (Bb) is roughly 0.462 or 46.2%.