Assume the random variable ( mathrm{X} ) is normally distributed, with mean ( mu=52 ) and standard deviation ( sigma=5 ). Find the 15 th percentile. The 15 th percentile is (Round to two decimal places as needed.)

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Assume the random variable  (  mathrm{X}  ) is normally distributed, with mean  (  mu=52  ) and standard deviation  (  sigma=5  ). Find the 15 th percentile. The 15 th percentile is (Round to two decimal places as needed.)

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(Solved): Assume the random variable \( \mathrm{X} \) is normally distributed, with mean \( \mu=52 \) and sta ...

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