(Solved): Assume the random variable x is normally distributed with mean =83 and standard deviation =5. F ...
Assume the random variable x is normally distributed with mean μ=83 and standard deviation σ=5. Find the indicated probability. P(68<x<75)P(68<x<75)= (Round to four decimal places as needed.)
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Use the normal distrbution of SAT eritical reading soares for which the mesn is 510 and the standard deviason is 111 : Assume the variable x is normaly distrbuled. (a) What percent of the SAT verbai scorbs are less than 550 ? (b) If 1000 SAT verbw scores ace randomvy selected, about how enany would you expect to be greater than 525 ? (a) Approximarely of the 5AT vertial scores are less than 550 . (Round to two dedimal places as neseded.) (b) You would expect that appronimately SAT verbal tcores would be greater than 525 . (Round to the nesrest whole number as needed.) Standard Normal Table (Page 1) −∞ Standard Normal Table (Page 2)
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P. Standard Normal Table (Page 2) −x Stakdard Normal Table (Page 1) - a d o 34 .
Find the indicated z-score shown in the graph to the right. The z-score is (Round to two decimal places as needed.)