(Solved): At some instant the velocity components of an electron moving between two charged parallel plates ...

At some instant the velocity components of an electron moving between two charged parallel plates are \( v_{x}=1.6 \times 10^{5} \mathrm{~m} / \mathrm{s} \) and \( v_{y}=3.4 \times 10^{3} \mathrm{~m} / \mathrm{s} \). Suppose the electric field between the plates is uniform and given by \( \vec{E}=(120 \mathrm{~N} / \mathrm{C}) \vec{j} \). In unit-vector notation, what are (a) the electron's acceleration in that field and (b) the electron's velocity when its \( x \) coordinate has changed by \( 2.0 \mathrm{~cm} \) ? (a) ( \( \hat{\mathrm{j}} \) (b) ( \( \widehat{\mathrm{i}}+( \) In the figure an electron is shot at an initial speed of \( v_{0}=5.74 \times 10^{6} \mathrm{~m} / \mathrm{s} \), at angle \( \theta_{0}=41.7^{\circ} \) from an \( x \) axis. It moves through a uniform electric field \( \vec{E}=(5.97 \mathrm{~N} / \mathrm{C}) \vec{j} \). A screen for detecting electrons is positioned parallel to the \( y \) axis, at distance \( x=2.17 \mathrm{~m} \). What is the \( y \) component of the electron's velocity (sign included) when the electron hits the screen? Number Units An electric dipole consisting of charges of magnitude \( 3.10 \mathrm{nC} \) separated by \( 7.70 \mu \mathrm{m} \) is in an electric field of strength \( 1140 \mathrm{~N} / \mathrm{C} \). What are (a) the magnitude of the electric dipole moment and (b) the difference between the potential energies for dipole orientations parallel and antiparallel to \( \vec{E} \) ? (a) Number Units (b) Number Units eTextbook and Media