(Solved): At the end of a filtration cycle, a total volume of 4.50m^(3) is collected in a total time of 272. ...
At the end of a filtration cycle, a total volume of
4.50m^(3)is collected in a total time of
272.6s. The cake is to be washed through washing in the plate-and-frame press using a volume of wash water equal to
10%of the filtrate volume. From the filtration data intercept
B=16.50(s)/(m^(3))and
K_(p)=38.82(s)/(m^(6))Calculate 6.1 The time of washing 6.2 The total filter cycle time if cleaning the filter takes 20 minutes. For the filter the filtration rate is
((dV)/(dt))_(f)=(1)/(4)(1)/((K_(p))(V_(f))+B)(in a plate and frame press, the flow of wash water is one quarter of the filtration rate.) 6.3 Aqueous slurry of
CaCO_(3)is to be filtered in a rotary drum filter with
25%submergence of area is covered by slurry). The available pressure drop is
75kPaand the cycle time is 6 minutes. The slurry contains
240kgsolids per cubic meters of slurry and density of solids is
2850k(g)/(m^(3)). The filter cake contains
45%moisture on wet basis and the specific cake resistance is
1.23\times 10^(11)(m)/(k)g. Calculate the filter area required to fijter 40 litres/minute. The resistance of the filter medium maybe neglected. Take
\mu _(slury )=0.001k(g)/(m),sThe expression for the area in terms of filtrate flow rate
(V_(f))/(\theta _(c))is given below
A=((V_(f))/(\theta _(c)))*\sqrt(((s\rho \mu \alpha _(ave)\theta _(c))/(2Pk_(f)(1-ms))))Where
\theta _(c)is the cycie time and
k_(f)is the fractional submergence
