Home / Expert Answers / Chemical Engineering / at-the-end-of-a-filtration-cycle-a-total-volume-of-4-50m-3-is-collected-in-a-total-time-of-272-pa457

# (Solved): At the end of a filtration cycle, a total volume of 4.50m^(3) is collected in a total time of 272. ...

At the end of a filtration cycle, a total volume of

4.50m^(3)

is collected in a total time of

272.6s

. The cake is to be washed through washing in the plate-and-frame press using a volume of wash water equal to

10%

of the filtrate volume. From the filtration data intercept

B=16.50(s)/(m^(3))

and

K_(p)=38.82(s)/(m^(6))

Calculate 6.1 The time of washing 6.2 The total filter cycle time if cleaning the filter takes 20 minutes. For the filter the filtration rate is

((dV)/(dt))_(f)=(1)/(4)(1)/((K_(p))(V_(f))+B)

(in a plate and frame press, the flow of wash water is one quarter of the filtration rate.) 6.3 Aqueous slurry of

CaCO_(3)

is to be filtered in a rotary drum filter with

25%

submergence of area is covered by slurry). The available pressure drop is

75kPa

and the cycle time is 6 minutes. The slurry contains

240kg

solids per cubic meters of slurry and density of solids is

2850k(g)/(m^(3))

. The filter cake contains

45%

moisture on wet basis and the specific cake resistance is

1.23\times 10^(11)(m)/(k)g

. Calculate the filter area required to fijter 40 litres/minute. The resistance of the filter medium maybe neglected. Take

\mu _(slury )=0.001k(g)/(m),s

The expression for the area in terms of filtrate flow rate

(V_(f))/(\theta _(c))

is given below

A=((V_(f))/(\theta _(c)))*\sqrt(((s\rho \mu \alpha _(ave)\theta _(c))/(2Pk_(f)(1-ms))))

Where

\theta _(c)

is the cycie time and

k_(f)

is the fractional submergence

We have an Answer from Expert