[ begin{array}{l} p=d(x)=107-x^{2} p=s(x)=3 x^{2}-20 x-93 end{array} ] where ( x ) is the number of hundreds of jerseys and ( p ) is the price in dollars. Find the equilibrium point. Equilibrium quantity, ( x= ) , which corresponds to jerseys. Equilibrium price, ( p= ) dollars.

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[  begin{array}{l} p=d(x)=107-x^{2}    p=s(x)=3 x^{2}-20 x-93  end{array}  ] where  ( x  ) is the number of hundreds of jerseys and  ( p  ) is the price in dollars. Find the equilibrium point. Equilibrium quantity,  ( x=  ) , which corresponds to jerseys. Equilibrium price,  ( p=  ) dollars.

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(Solved): \[ \begin{array}{l} p=d(x)=107-x^{2} \\ p=s(x)=3 x^{2}-20 x-93 \end{array} \] where \( x \) is the ...

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