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(Solved): \[ \begin{array}{l} p=d(x)=107-x^{2} \\ p=s(x)=3 x^{2}-20 x-93 \end{array} \] where \( x \) is the ...



\[
\begin{array}{l}
p=d(x)=107-x^{2} \\
p=s(x)=3 x^{2}-20 x-93
\end{array}
\]
where \( x \) is the number of hundreds of jers

\[ \begin{array}{l} p=d(x)=107-x^{2} \\ p=s(x)=3 x^{2}-20 x-93 \end{array} \] where \( x \) is the number of hundreds of jerseys and \( p \) is the price in dollars. Find the equilibrium point. Equilibrium quantity, \( x= \) , which corresponds to jerseys. Equilibrium price, \( p= \) dollars.


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