Calculate the mass of lead sulfide that could be made when 85.0 mL of 0.500 M lead nitrate reacts with excess sodium sulfide according to the following reaction:

Pb(NO3)2(aq) + Na2S(aq) à PbS(s) + 2NaNO3(a

Intro to chemistry help please!

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Calculate the mass of lead sulfide that could be made when 85.0 mL of 0.500 M lead nitrate reacts with excess sodium sulfide according to the following reaction:

Pb(NO3)2(aq) + Na2S(aq) à PbS(s) + 2NaNO3(a

Intro to chemistry help please!

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