(Solved): Can I please get an explenation of how we got to the step where i marked with blue saying "why this ...

Ex \ Prove \( \frac{1+\sin x}{1-\sin x}=(\tan x+\sec x)^{2} \) \[ \text { LHS }=\frac{(1+\sin x)(1+\sin x)}{(1+\sin x)(1-\sin x)}=\frac{(1+\sin x)^{2}}{\left(1-\sin ^{2} x\right)} \] \[ \begin{array}{l} \text { LHS }=\frac{(1+\sin x)^{2}}{\cos ^{2} x} \quad * \quad \sin ^{2} \theta+\cos ^{2} \theta=1 \\ \text { LHS }=\left(\frac{1+\sin x}{\cos x}\right)^{2}= \\ \left(\frac{1}{\cos x}+\frac{\sin x}{\cos x}\right)^{2}=(\sec x+\tan x)^{2} \\ \end{array} \]