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(Solved): can you solve it fast 8. [3/6 Points] Consider the following. v=sin(3s22t2) Find the first part ...
can you solve it fast
8. [3/6 Points] Consider the following. v=sin(3s2−2t2) Find the first partial derivatives. v5=vt= Find all the second partial derivatives. vss=6cos(3s2−2t2)−36s2sin(3s2−2t2)vst=−12stcos(3s2−2t2)−12ssin(3s2−2t2)vts=vtt=4tcos(3s2−2t2)−16t3sin(3s2−2t2)