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Consider a test of Ho: μ=75 performed with the computer. The software reports a two-tailed p-value of 0.1032. Make the appropriate conclusion for each of the following situations. a. H₂: μ<75, z = -1.63, α = 0.03 b. H₂: μ< 75, z = 1.63, α = 0.06 c. H₂ μ>75, z= 1.63, α=0.06 d. H₂ μ not = 75, z = -1.63, α=0.01

Consider a test of $H_{0}:μ=75$ performed with the computer. The software reports a two-tailed p-value of 0.1032 . Make the appropriate conclusion for each of the following situations. a. $H_{a}:μ<75,z=−1.63,α=0.03$ b. $H_{a}:μ<75,z=1.63,α=0.06$ c. $H_{a}:μ>75,z=1.63,α=0.06$ d. $H_{a}:μ=75,z=−1.63,α=0.01$

(a)

H0 : = 75

Ha : < 75 (left tailed)

The test statistic, z = -1.63

p-value = P(Z<-1.63) = 0.1032/2 = 0.0516

= 0.03

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