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(Solved): Consider the differential equation (dP)/(dt)=kP^(1+c) where k>0 and c>=0. In Section 3.1 we sa ...



Consider the differential equation (dP)/(dt)=kP^(1+c) where k>0 and c>=0. In Section 3.1 we saw that in the case c=0 the linear differential equation d(P)/(d)t=kP is a mathematical model of a population P(t) that exhibits unbounded growth over the infinite time interval [0,\infty ), that is, P(t)->\infty as t->\infty . See Example 1 in that section. (a) Suppose for c=0.01 that the nonlinear differential equation (dP)/(dt)=kP^(1.01),k>0 is a mathematical model for a population of small animals, where time t is measured in months. Solve the differential equation subject to the initial condition P(0)=10t to six decimal places.P(t)=((1)/(0.977237-0.001125t))100 (b) The differential equation in part (a) is called a doomsday equation because the population P(t) exhibits unbounded growth over a finite time interval (0,T), that is, there is some time T such that P(t)->\infty as t->T^(-). Find T. (Round your answer to the nearest month.) T= months (c) From part (a), what is P(70) ? P(140) ? (Round your answers to the nearest whole number.) P(70)= P(140)=


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