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Consider the following initial value problem: $y_{′′}−2y_{′}−35y=sin(6t)y(0)=1,y_{′}(0)=2$ Using $Y$ for the Laplace transform of $y(t)$, i.e., $Y=L{y(t)}$, find the equation you get by taking the Laplace transform of the differential equation and solve for $Y(s)$

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