(Solved): Consider the system \( A \mathbf{x}=\mathbf{b} \) where \( A=\left[\begin{array}{cc}2 & -2 \\ 4 & ...

Consider the system \( A \mathbf{x}=\mathbf{b} \) where \( A=\left[\begin{array}{cc}2 & -2 \\ 4 & -4\end{array}\right] \) and \( \mathbf{b}=\left[\begin{array}{c}2 \\ -2\end{array}\right] \). A basis for the null space of \( A \) is given by \( \left\{\left[\begin{array}{l}1 \\ 1\end{array}\right]\right\} \) and \( \mathbf{x}=\left[\begin{array}{l}1 \\ 0\end{array}\right] \) is a particular solution. Use this information to find the row space solution \( \mathbf{x}_{r} \) to \( A \mathbf{x}=\mathbf{b} \). \[ \mathbf{x}_{r}=[\quad] \]