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(Do not reference current solutions, you must do all work from scratch and methodically correct).

In the figure, a baseball is hit at a height $h=1.10m$ and then caught at the same height. It travels alongside a wall, moving up past the top of the wall $1.1s$ after it is hit and then down past the top of the wall $4.7s$ later, at distance $D=58m$ farther along the wall. (a) What horizontal distance is traveled by the ball from hit to catch? What are the (b) magnitude and (c) angle (relative to the horizontal) of the ball's velocity just after being hit? (d) How high is the wall?

According to the given values, distance D covered by the baseball in 4.7 s.

So the horizontal velocity is m/s

Total time taken by the baseball is

s

Since for the projectile motion, time of flight is equal to the time of fall. Since time taken by baseball to cross D distance is 4.7 s.

Part (a)

Horizontal distance travelled by the baseball is