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(Solved): \( \dot{x}=x-2 y+1, \quad \dot{y}=x+4 y-4, x(0)=1, y(0)=0 \) ...



\( \dot{x}=x-2 y+1, \quad \dot{y}=x+4 y-4, x(0)=1, y(0)=0 \)
\( \dot{x}=x-2 y+1, \quad \dot{y}=x+4 y-4, x(0)=1, y(0)=0 \)


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With system of differential equation x?=x?2y+1 y?=x+4y?4 differen
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