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(Solved): Each year a certain magazine publishes a list of "Best Places to Live in the United States." These l ...



Each year a certain magazine publishes a list of "Best Places to Live in the United States." These listings are based on affordability, educational performance, convenience, safety, and livability. Suppose the list below shows the median household income of the magazine's top city in each U.S. state for a certain year. (Round your answers to the nearest cent.) CityMedian Household Income ($)CityMedian Household Income ($)Pelham, AL66,768Bozeman, MT49,299Juneau, AK84,097Papillion, NE79,127Paradise Valley, AZ138,188Sparks, NV54,226Fayetteville, AR40,831Nashua, NH66,868Monterey Park, CA57,415North Arlington, NJ73,881Lone Tree, CO116,757Rio Rancho, NM58,978Manchester, CT64,824Valley Stream, NY88,689Hockessin, DE115,120Concord, NC54,575St. Augustine, FL47,744Dickinson, ND71,862Vinings, GA73,099Wooster, OH43,050Kapaa, HI62,542Mustang, OK66,710Meridian, ID62,895Beaverton, OR58,781Schaumburg, IL73,820Lower Merion, PA117,434Fishers, IN87,039Warwick, RI63,410Council Bluffs, IA46,840Mauldin, SC57,476Lenexa, KS76,501Rapid City, SD47,784Georgetown, KY58,705Franklin, TN82,330Bossier City, LA47,047Allen, TX104,520South Portland, ME56,468Orem, UT54,511Rockville, MD100,154Colchester, VT69,177Waltham, MA75,102Reston, VA112,718Farmington Hills, MI71,150Mercer Island, WA128,480Woodbury, MN99,653Morgantown, WV38,056Olive Branch, MS62,954New Berlin, WI74,979St. Peters, MO57,724Cheyenne, WY56,589 (a) Compute the mean and median (in $) for these household income data. mean$median$ (b) Compare the mean and median values for these data. What does this indicate about the distribution of household income data? The mean household income is ---Select--- smaller than larger than the same as the median household income. This indicates that the distribution of household income is ---Select--- positively skewed (skewed right). negatively skewed (skewed left). symmetric. (c) Compute the range and standard deviation (in $) for these household income data. (Round your standard deviation to the nearest cent.) range$standard deviation$ (d) Compute the first and third quartiles (in $) for these household income data. Q1$Q3$ (e) Are there any outliers in these data? There ---Select--- are 0 values is 1 value are 2 values are 3 values are 4 values below the lower limit and ---Select--- 0 values 1 value 2 values 3 values 4 values above the upper limit. What does this suggest about the data? There are no outliers in the data, which is likely why the mean value is less than the median.There are outliers in the data, which is likely why the mean value is less than the median. There are no outliers in the data, which is likely why the mean value is the same as the median.There are outliers in the data, which is likely why the mean value is greater than the median.There are no outliers in the data, which is likely why the mean value is greater than the median.



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