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(Solved): Evaluate Subscript n Baseline Upper C Subscript x Baseline p Superscript x Baseline left parenthesis ...



Evaluate Subscript n Baseline Upper C Subscript x Baseline p Superscript x Baseline left parenthesis 1 minus p right parenthesis Superscript n minus xnCxpx(1−p)n−x for nequals=4​, pequals=0.22​, xequals=1.



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