(Solved): Evaluate Subscript n Baseline Upper C Subscript x Baseline p Superscript x Baseline left parenthesis ...
Evaluate Subscript n Baseline Upper C Subscript x Baseline p Superscript x Baseline left parenthesis 1 minus p right parenthesis Superscript n minus xnCxpx(1−p)n−x for nequals=4, pequals=0.22, xequals=1.