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(Solved): evaluate this surface integral 4. Sy2z2dS,S is the part of the cone y=x2+z2 given by 0y ...



evaluate this surface integral

4. \( \iint_{S} y^{2} z^{2} d S, S \) is the part of the cone \( y=\sqrt{x^{2}+z^{2}} \) given by \( 0 \leqslant y \leqslant
4. is the part of the cone given by


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