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(Solved): evaluate using trig substitution \( \frac{1}{x^{2} \sqrt{x^{2}-25}} d x \) ...


evaluate using trig substitution

\( \frac{1}{x^{2} \sqrt{x^{2}-25}} d x \)
\( \frac{1}{x^{2} \sqrt{x^{2}-25}} d x \)


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we have that ?1x2(x2?25)dx using trig substitution x=5sec?u so that dx=5(sec?u)(tan?u)du and x2?25=(5sec?u)2?25=25sec2u?25 which gives us 25(sec2u?1)=
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