(Solved): Find all solutions (real or complex) for each of the following equations: - x26x+10=0 - x3+x1 ...

Expert Answer

---

1.) To find the solutions for the quadratic equation x^2 - 6x + 10 = 0, we can use the quadratic formula:
x = (-b ± sqrt(b^2 - 4ac)) / 2a
where a = 1, b = -6, and c = 10. Substituting these values, we get:
x = (6 ± sqrt((-6)^2 - 4(1)(10))) / 2(1) x = (6 ± sqrt(36 - 40)) / 2 x = (6 ± sqrt(-4)) / 2 x = 3 ± i
Therefore, the solutions are x = 3 + i and x = 3 - i.